There are many ways for checking whether the array contains any specific value or not, one of them is:
Examples:
Input: arr[] = {10, 30, 15, 17, 39, 13}, key = 17
Output: True
Input: arr[] = {3, 2, 1, 7, 10, 13}, key = 20
Output: False
Approach:
Using in-built functions: In C language there is no in-built function for searching
C++
#include <bits/stdc++.h>
using namespace std;
int main()
{
vector<int> v{ 10, 25, 15, 12, 14 };
int key = 15;
if (find(v.begin(), v.end(), key) != v.end())
cout << key << " is present in the array";
else
cout << key << " is not present in the array";
return 0;
}
|
Java
import java.io.*;
import java.util.Arrays;
class GFG {
public static void main(String[] args)
{
Integer arr[] = { 10, 25, 15, 12, 14 };
int key = 15;
boolean found = Arrays.asList(arr).contains(key);
if (found == true) {
System.out.println(
key + " is present in the array");
}
else {
System.out.println(
key + " is not present in the array");
}
}
}
|
Python3
if __name__ == '__main__':
arr = [10, 25, 15, 12, 14]
key = 15
found = False
if key in arr:
found = True
if found == True:
print(key, end = " is present in the array")
else:
print(key, end = " is not present in the array")
|
PHP
<?php
$arr = array(10, 25, 15, 12, 14);
$key = 15;
if (in_array("$key", $arr)){
echo "$key is present in the array";
}
else{
echo "$key is not present in the array";
}
?>
|
Javascript
<script>
const arr = [10, 25, 15, 12, 14];
const key = 15
if(arr.includes(key) == true){
console.log( key + " is present in the array");
}
else{
console.log( key + " is not present in the array");
}
</script>
|
Output
15 is present in the array
Apart from these inbuilt functions, there are other methods that one can use like:
